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One card is selected at random from a deck of cards. Determine the probability that the card selected is a 9?

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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固有ベクトル (

4	4	2	3	−2
0	1	−2	−2	2
6	12	11	2	−4
9	20	10	10	−6
15	28	14	5	−3

)

Solution

(

−3

), (

−2

), (

−2

), (

−1

), (

)

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Solution steps

One step at a time

(

4	4	2	3	−2
0	1	−2	−2	2
6	12	11	2	−4
9	20	10	10	−6
15	28	14	5	−3

)

行列の固有ベクトル

A は正方行列,η はベクトル,λ はスカラーで Aη=λη を満たすとする。
ならば,η は A の固有ベクトルで,λ はそれに関連する固有値である

固有ベクトル η を求めるには,各固有値で (A−λ I)η=0 を解く λ

以下の固有値を求める: (

4	4	2	3	−2
0	1	−2	−2	2
6	12	11	2	−4
9	20	10	10	−6
15	28	14	5	−3

): λ=3以下の重複度: 2, λ=5以下の重複度: 2, λ=7

以下の固有ベクトル: λ=3: (

−3

), (

−2

)

以下の固有ベクトル: λ=5: (

−2

), (

−1

)

以下の固有ベクトル: λ=7: (

)

以下の固有ベクトル: (

4	4	2	3	−2
0	1	−2	−2	2
6	12	11	2	−4
9	20	10	10	−6
15	28	14	5	−3

)

−3

), (

−2

), (

−2

), (

−1

), (

)

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こんにちは, について質問する固有ベクトル (

4	4	2	3	−2
0	1	−2	−2	2
6	12	11	2	−4
9	20	10	10	−6
15	28	14	5	−3

) または以下を選択してください

−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

One card is selected at random from a deck of cards. Determine the probability that the card selected is a 9?

Solution

Solution steps

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