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lcm 3/(x^2-6), (5-x)/(2x-12)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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準線 y=1−x²

Solution

y=54

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放物線の準線

放物線は複数の点の軌跡であり,1つの点（焦点）までの距離は1つの線（準線）までの距離に等しい

放物線の標準的なequation

4p(y−k)=(x−h)² は上下に面する放物線の標準的なequationで,頂点は (h, k),
焦点距離は |p| である

y=1−x² を標準的な形式で書き換える: 4(−14 )(y−1)=(x−0)²

(h, k)=(0, 1), p=−14

放物線は y 軸に対して対称で,準線は x 軸に平行で中心 (0, 1) の y 座標から距離 −p にある

y=1−p

y=1−(−14 )

改良

y=54

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こんにちは, について質問する準線 y=1−x² または以下を選択してください

−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

lcm 3/(x^2-6), (5-x)/(2x-12)

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