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範囲 sin(5x)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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逆ラプラス (5x−20)(x−4)

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L⁻¹{(5x−20)(x−4) }

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=L⁻¹{5xx−4 −20x−4 }

逆ラプラス変換の線形性を使用する:
関数 f(s), g(s) と定数 a, b: L⁻¹{a·f(s)+b·g(s)}=a·L⁻¹{f(s)}+b·L⁻¹{g(s)}

=5L⁻¹{xx−4 }−20L⁻¹{1x−4 }

L⁻¹{xx−4 }: e^4t· 4+1

L⁻¹{1x−4 }: e^4t

=5(e^4t· 4+1)−20e^4t

簡素化 5· (e^4t· 4+1)−20· e^4t: 5

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こんにちは, について質問する逆ラプラス (5x−20)(x−4) または以下を選択してください

−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

範囲 sin(5x)

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