(\partial^2)/(\partial y\partial x)(((xy^3-x^3y))/(x^2+y^2))

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軸 9x²+4y²=1

Solution

半長径 b=12 , 半短径 a=13

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9x²+4y²=1

楕円の標準equation

(x−h)²a² +(y−k)²b² =1 は楕円の標準equation
中心は (h, k),a, b は長半径と短半径

9x²+4y²=1 を標準的な楕円のequationの形式で書き換える

(x−0)²(13 )² +(y−0)²(12 )² =1

ゆえに楕円の特性は:

(h, k)=(0, 0), a=13 , b=12

b>a ゆえに b は半長径,a は半短径である

中心が (h, k)=(0, 0), b=12 , a=13 の楕円

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対象 9x²+4y²=1

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こんにちは, について質問する軸 9x²+4y²=1 または以下のオプションから選択してください

それより解答対象 9x²+4y²=1

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

(\partial^2)/(\partial y\partial x)(((xy^3-x^3y))/(x^2+y^2))

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(\partial^2)/(\partial y\partial x)(((xy^3-x^3y))/(x^2+y^2))

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