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center (x-4)^2+(y+2)^2=25

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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center (x−4)²+(y+2)²=25

Solution

(4, −2)

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(x−4)²+(y+2)²=25

Circle Equation

(x−a)²+(y−b)²=r² is the circle equation with a radius r, centered at (a, b)

Rewrite (x−4)²+(y+2)²=25 in the form of the standard circle equation

(x−4)²+(y−(−2))²=5²

Therefore the circle properties are:

(a, b)=(4, −2), r=5

And the center is:

(4, −2)

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こんにちは, について質問する center (x−4)²+(y+2)²=25 または以下を選択してください

−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

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center (x-4)^2+(y+2)^2=25

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center (x-4)^2+(y+2)^2=25

Solution

Solution steps

Number Line

Graph