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切片 √x2+1
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Solution
Y切片:(0,1)
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楕円の焦点
長径が y 軸に平行している楕円では,焦点は次のように定義される: (h,k+c),(h,k−c) ここで c=√b2−a2は中心 (h,k)から焦点までの距離
