directrix y=x^2+1

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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f(a)=2a⁻⁴a²3a⁶

Solution

定義域: a<0 or a>0

範囲: f(x)>0

切片: なし

漸近線: 水平 y=6a⁴

極値点: なし

Interval Notation

定義域: (−∞ , 0)∪(0, ∞ )

範囲: (0, ∞ )

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∫ 4x²−2x+12x+3 dx

拡張 4x²−2x+12x+3 : 4x²2x+3 −2x2x+3 +12x+3

総和規則を適用する: ∫f(x)±g(x)dx=∫f(x)dx±∫g(x)dx

=∫ 4x²2x+3 dx−∫ 2x2x+3 dx+∫ 12x+3 dx

∫ 4x²2x+3 dx=14 (4x²−12x+18ln|2x+3|−27)

∫ 2x2x+3 dx=x+32 −32 ln|2x+3|

∫ 12x+3 dx=12 ln|2x+3|

=14 (4x²−12x+18ln|2x+3|−27)−(x+32 −32 ln|2x+3|)+12 ln|2x+3|

簡素化 14 (4x²−12x+18ln|2x+3|−27)−(x+32 −32 ln|2x+3|)+12 ln|2x+3|: x²−4x+132 ln|2x+3|−32 −274

=x²−4x+132 ln|2x+3|−32 −274

定数を解答に追加する

=x²−4x+132 ln|2x+3|−32 −274 +C

Solve instead

逆 2a⁻⁴a²3a⁶

偶奇性 2a⁻⁴a²3a⁶

対象 2a⁻⁴a²3a⁶

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こんにちは, について質問する f(a)=2a⁻⁴a²3a⁶ または以下のオプションから選択してください

何か他のことを解決したい

−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

directrix y=x^2+1

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directrix y=x^2+1

Solution

Solution steps

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