切片 20((x-3)(x+4))/((x-3)^2(x-5))

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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intercepts 20(x−3)(x+4)(x−3)²(x−5)

Solution

X Intercepts: (−4, 0), Y Intercepts: (0, 163 )

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x−axis interception points of 20(x−3)(x+4)(x−3)²(x−5) : (−4, 0)

y−axis interception point of 20(x−3)(x+4)(x−3)²(x−5) : (0, 163 )

X Intercepts: (−4, 0), Y Intercepts: (0, 163 )

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こんにちは, について質問する intercepts 20(x−3)(x+4)(x−3)²(x−5) または以下のオプションから選択してください

関数の切片を見つける方法を説明する

−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

切片 20((x-3)(x+4))/((x-3)^2(x-5))

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切片 20((x-3)(x+4))/((x-3)^2(x-5))

Solution

Solution steps

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