f(x)=(4x^3-x^2+x-2)-(-x^2+3)

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f(x)=(4x³−x²+x−2)−(−x²+3)

Solution

Domain: −∞ <x<∞

Range: −∞ <f(x)<∞

X Intercepts: (1, 0), Y Intercepts: (0, −5)

Asymptotes: None

Extreme Points: None

Interval Notation

Domain: (−∞ , ∞ )

Range: (−∞ , ∞ )

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Domain of 4x³−x²+x−2−(−x²+3) : −∞ <x<∞

Range of 4x³−x²+x−2−(−x²+3): −∞ <f(x)<∞

Axis interception points of 4x³−x²+x−2−(−x²+3): X Intercepts: (1, 0), Y Intercepts: (0, −5)

Asymptotes of 4x³−x²+x−2−(−x²+3): None

Extreme Points of 4x³−x²+x−2−(−x²+3): None

Solve instead

ddx ((4x³−x²+x−2)−(−x²+3))

inverse 4x³−x²+x−2−(−x²+3)

parity 4x³−x²+x−2−(−x²+3)

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こんにちは, について質問する f(x)=(4x³−x²+x−2)−(−x²+3) または以下のオプションから選択してください

何か他のことを解決したい

−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

f(x)=(4x^3-x^2+x-2)-(-x^2+3)

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