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x
2
x
□
log
□
√
☐
□
√
☐
≤
≥
□
□
·
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x
◦
π
(
☐
)
′
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dx
∂
∂
x
∫
∫
□
□
lim
∑
∞
θ
(
f
◦
g
)
f
(
x
)
−
▭
▭
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7
8
9
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+
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d
dx
(
4
x
−
7
x
2
+
5
x
)
Verify
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Solution
−
4
x
2
+
1
4
x
+
3
5
(
x
2
+
5
x
)
2
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d
dx
(
4
x
−
7
x
2
+
5
x
)
商の法則を適用:
(
f
g
)
′
=
f
′
·
g
−
g
′
·
f
g
2
=
d
dx
(
4
x
−
7
)
(
x
2
+
5
x
)
−
d
dx
(
x
2
+
5
x
)
(
4
x
−
7
)
(
x
2
+
5
x
)
2
d
dx
(
4
x
−
7
)
=
4
d
dx
(
x
2
+
5
x
)
=
2
x
+
5
=
4
(
x
2
+
5
x
)
−
(
2
x
+
5
)
(
4
x
−
7
)
(
x
2
+
5
x
)
2
拡張
4
(
x
2
+
5
x
)
−
(
2
x
+
5
)
(
4
x
−
7
)
:
−
4
x
2
+
1
4
x
+
3
5
=
−
4
x
2
+
1
4
x
+
3
5
(
x
2
+
5
x
)
2
Practice Quotient Rule
Number Line
Graph
Plotting:
y
=
−
4
x
2
+
1
4
x
+
3
5
(
x
2
+
5
x
)
2
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4
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7
x
2
+
5
x
)
逆ラプラス
4
x
−
7
x
2
+
5
x
Negative Exponents Examples
4
−
1
(
−
7
)
−
2
x
−
6
Description
Apply the negative exponent rule step-by-step
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逆 $$2^{x+1}$$
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x
2
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5
x
)
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