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範囲 x^2+2x-1-(2x^2-3x+6)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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証明する tan²(x)−sin²(x)=tan²(x)sin²(x)

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tan²(x)−sin²(x)=tan²(x)sin²(x)

右側を操作する

tan²(x)sin²(x)

三角関数の公式を使用して書き換える

=tan²(x)(1−cos²(x))

拡張 (1−cos²(x))tan²(x): tan²(x)−tan²(x)cos²(x)

=tan²(x)−cos²(x)tan²(x)

三角関数の公式を使用して書き換える

=tan²(x)−sin²(x)

両辺を同じ形式にできることを証明した

⇒ 真

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こんにちは, について質問する証明する tan²(x)−sin²(x)=tan²(x)sin²(x) または以下のオプションから選択してください

−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

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範囲 x^2+2x-1-(2x^2-3x+6)

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