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surjective y=sin{x}

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(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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範囲 (x+5)²

Solution

f(x)≥ 0

Interval Notation

[0, ∞ )

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関数範囲の定義

関数が定義されている従属変数の値の集合

以下の頂点: (x+5)²: 最小値 (−5, 0)

放物線 ax²+bx+c で以下の頂点がある場合: (x_v, y_v)
a<0 であれば,範囲は f(x)≤ y_v
a>0 であれば,範囲は f(x)≥ y_v
a=1, Vertex (x_v, y_v)=(−5, 0)

f(x)≥ 0

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領域 (x+5)²

頂点 (x+5)²

逆 (x+5)²

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こんにちは, について質問する範囲 (x+5)² または以下のオプションから選択してください

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

surjective y=sin{x}

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surjective y=sin{x}

Solution

Solution steps

Solve instead

Number Line

Graph