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reciprocal of y=(4x+24)/(x-6)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

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√☐

^□√☐

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log_□

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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中央値 1, 7, −3, 4, 9

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中央値

中央値はデータセットの上位半分を下位半分から分離する値である。
項の数が偶数であれば,中央値は並べ替えられた集合の中央元である
項の数が奇数であれば,中央値は並べ替えられた集合の 2 つの中央元の等差中項である

昇順で項を並べる

−3, 1, 4, 7, 9

昇順集合の中央値を求める: 4

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こんにちは, について質問する中央値 1,7,−3,4,9

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

reciprocal of y=(4x+24)/(x-6)

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