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切片 log_{4}(x-1)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

simplify solve for inverse tangent line

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ミッドヒンジ 0.42, 0.52, 0.58, 0.62

Solution

0.535

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関数範囲の定義

関数が定義されている従属変数の値の集合

定義済みの各区間の最小値と最大値を求め,計算結果を結合する

以下の領域: tan²(x)+1 : πn≤ x<π2 +πn or π2 +πn<x<π+πn

以下の極点: tan²(x)+1: 最小値(πn, 1)

区間の範囲を求める 0≤ x<π2 : 1≤ f(x)<∞

区間の範囲を求める π2 <x<π: 1≤ f(x)<∞

あらゆる領域区間の範囲を組み合わせて関数範囲を求める

f(x)≥ 1 or f(x)≥ 1

f(x)≥ 1

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

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切片 log_{4}(x-1)

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