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頂点 x^2+1

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部分 ∫ e^x1+e^2x dx

Solution

arctan(e^x)+C

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∫ e^x1+e^2x dx

部分積分を適用する: e^x1+e^2x −∫ −2e^3x(1+e^2x)² dx

=e^x1+e^2x −∫ −2e^3x(1+e^2x)² dx

∫ −2e^3x(1+e^2x)² dx=e^x1+e^2x −arctan(e^x)

=e^x1+e^2x −(e^x1+e^2x −arctan(e^x))

簡素化

=arctan(e^x)

定数を解答に追加する

=arctan(e^x)+C

Verify Result

=arctan(e^x)+C

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こんにちは, について質問する部分 ∫ e^x1+e^2x dx または以下を選択してください

−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

頂点 x^2+1

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頂点 x^2+1

Solution

Solution steps

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