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数列の種類 a_{1}=-2,d=3

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垂直線 y=−5x+2, x=1

Solution

y=15 x−165

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y=−5x+2と直角をなして通過する線 y=mx+bを見つける x=1

鉛直点を見つける: (1, −3)

以下の傾斜を見つける: y=−5x+2: m=−5

垂直線の傾斜を計算する: m_p=15

傾斜m=15 で通過する線を見つける (1, −3): y=15 x−165

y=15 x−165

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こんにちは, について質問する垂直線 y=−5x+2,x=1

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

数列の種類 a_{1}=-2,d=3

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