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laplace transform e^{2x}

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∫ xcos(2x)dx

Solution

14 (2xsin(2x)+cos(2x))+C

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∫ xcos(2x)dx

u置換積分法を適用する: ∫ ucos(u)4 du

=∫ ucos(u)4 du

定数を除く: ∫a·f(x)dx=a·∫f(x)dx

=14 · ∫ ucos(u)du

部分積分を適用する: usin(u)−∫ sin(u)du

=14 (usin(u)−∫ sin(u)du)

∫ sin(u)du=−cos(u)

=14 (usin(u)−(−cos(u)))

代用を戻す u=2x

=14 (2xsin(2x)−(−cos(2x)))

簡素化

=14 (2xsin(2x)+cos(2x))

定数を解答に追加する

=14 (2xsin(2x)+cos(2x))+C

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こんにちは, について質問する ∫ xcos(2x)dx または以下のオプションから選択してください

−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

laplace transform e^{2x}

Solution

Solution steps

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1	−1	0
1	0	1
0	−1	1

1	1	1	2
1	0	1	−1
0	−1	−2	1
0	2	0	2

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laplace transform e^{2x}

Solution

Solution steps

Number Line

Graph