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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

Solutions > Matrix QR Decomposition Calculator >

領域 20((x-3)(x+4))/((x-3)^2(x-5))

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

π

θ

∞

∫

ddx

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Steps Examples

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固有ベクトル (

4	4	2	3	−2
0	1	−2	−2	2
6	12	11	2	−4
9	20	10	10	−6
15	28	14	5	−3

)

Solution

(

4

−3

1

2

0

), (

−2

1

1

0

2

), (

−2

2

0

−2

2

), (

0

−1

2

0

0

), (

1

0

0

3

3

)

Show Steps

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Solution steps

One step at a time

(

4	4	2	3	−2
0	1	−2	−2	2
6	12	11	2	−4
9	20	10	10	−6
15	28	14	5	−3

)

行列の固有ベクトル

A は正方行列,η はベクトル,λ はスカラーで Aη=λη を満たすとする。
ならば,η は A の固有ベクトルで,λ はそれに関連する固有値である

固有ベクトル η を求めるには,各固有値で (A−λ I)η=0 を解く λ

以下の固有値を求める: (

4	4	2	3	−2
0	1	−2	−2	2
6	12	11	2	−4
9	20	10	10	−6
15	28	14	5	−3

): λ=3以下の重複度: 2, λ=5以下の重複度: 2, λ=7

以下の固有ベクトル: λ=3: (

4

−3

1

2

0

), (

−2

1

1

0

2

)

以下の固有ベクトル: λ=5: (

−2

2

0

−2

2

), (

0

−1

2

0

0

)

以下の固有ベクトル: λ=7: (

1

0

0

3

3

)

以下の固有ベクトル: (

4	4	2	3	−2
0	1	−2	−2	2
6	12	11	2	−4
9	20	10	10	−6
15	28	14	5	−3

)

=(

4

−3

1

2

0

), (

−2

1

1

0

2

), (

−2

2

0

−2

2

), (

0

−1

2

0

0

), (

1

0

0

3

3

)

Matrix QR Decomposition Examples

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こんにちは, について質問する固有ベクトル (

4	4	2	3	−2
0	1	−2	−2	2
6	12	11	2	−4
9	20	10	10	−6
15	28	14	5	−3

) または以下を選択してください

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