compare ratios 5:1, 10:2

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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単調区間 √x²+1

Solution

減少中:−∞ <x<0, 増加中:0<x<∞

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単調区間の定義

f ′(x)>0 ならば, f(x) は増加する。
f ′(x)<0 ならば, f(x) は減少する。

f ′(x)=x√x²+1

区間を求める: 減少中:−∞ <x<0, 増加中:0<x<∞

減少中:−∞ <x<0, 増加中:0<x<∞

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領域 √x²+1

範囲 √x²+1

逆 √x²+1

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こんにちは, について質問する単調区間 √x²+1 または以下のオプションから選択してください

何か他のことを解決したい

−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

compare ratios 5:1, 10:2

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compare ratios 5:1, 10:2

Solution

Solution steps

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