integral from 1 to 16 of (x-7)/(sqrt(x))

解

\int_{1}^{16} \frac{x - 7}{x} d x

0

解答ステップ

\int_{1}^{16} \frac{x - 7}{x} d x

拡張

\frac{x - 7}{x} : x - \frac{7}{x}

= \int_{1}^{16} x - \frac{7}{x} d x

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{16} x d x - \int_{1}^{16} \frac{7}{x} d x

\int_{1}^{16} x d x = 42

\int_{1}^{16} \frac{7}{x} d x = 42

= 42 - 42

簡素化

= 0