半径 x^2+(y+3)^2=16

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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逆 log₂(2+x)−4

Solution

2^x+4−2

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逆関数の定義

y=f(x), x=g(y) であれば,関数 g は関数 f の逆である

y=log₂(2+x)−4

x を以下で置き換える: y

x=log₂(2+y)−4

yを解く x=log₂(2+y)−4

2^x+4−2

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領域 log₂(2+x)−4

範囲 log₂(2+x)−4

切片 log₂(2+x)−4

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

半径 x^2+(y+3)^2=16

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半径 x^2+(y+3)^2=16

Solution

Solution steps

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