切片 1/(x^3)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

☐²

x^☐

√☐

^□√☐

□□

log_□

θ

∞

∫

ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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逆ラプラス x²x²+1

Solution

δ(t)−sin(t)

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Solution steps

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L⁻¹{x²x²+1 }

以下の部分分数を得る: x²x²+1 : 1−1x²+1

=L⁻¹{1−1x²+1 }

逆ラプラス変換の線形性を使用する:
関数 f(s), g(s) と定数 a, b: L⁻¹{a·f(s)+b·g(s)}=a·L⁻¹{f(s)}+b·L⁻¹{g(s)}

=L⁻¹{1}−L⁻¹{1x²+1 }

L⁻¹{1}: δ(t)

L⁻¹{1x²+1 }: sin(t)

=δ(t)−sin(t)

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こんにちは, について質問する逆ラプラス x²x²+1 または以下を選択してください

−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

切片 1/(x^3)

Solution

Solution steps

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