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領域 sqrt(x+3)

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対象 4x(4x−2)(x²−3)

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(x−1)²9 +y²5 =100

楕円の標準equation

(x−h)²a² +(y−k)²b² =1 は楕円の標準equation
中心は (h, k),a, b は長半径と短半径

(x−1)²9 +y²5 =100 を標準的な楕円のequationの形式で書き換える

(x−1)²30² +(y−0)²(10√5)² =1

ゆえに楕円の特性は:

(h, k)=(1, 0), a=30, b=10√5

a>b ゆえに a は半長径,b は半短径である

中心が (h, k)=(1, 0), a=30, b=10√5 の楕円

中心は:

(1, 0)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

領域 sqrt(x+3)

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