derivative of 20cos(x)

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準線 y=3x²+4

Solution

y=4712

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放物線の準線

放物線は複数の点の軌跡であり,1つの点（焦点）までの距離は1つの線（準線）までの距離に等しい

放物線の標準的なequation

4p(y−k)=(x−h)² は上下に面する放物線の標準的なequationで,頂点は (h, k),
焦点距離は |p| である

y=3x²+4 を標準的な形式で書き換える: 4· 112 (y−4)=(x−0)²

(h, k)=(0, 4), p=112

放物線は y 軸に対して対称で,準線は x 軸に平行で中心 (0, 4) の y 座標から距離 −p にある

y=4−p

y=4−112

改良

y=4712

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こんにちは, について質問する準線 y=3x²+4 または以下を選択してください

−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

derivative of 20cos(x)

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