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頂点 7y^2+3y^2

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(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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vertices 7y²+3y²

Solution

(h, k)=(0, 0), p=140

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x=7y²+3y²

Parabola standard equation

4p(x−h)=(y−k)² is the standard equation for a right-left facing parabola with vertex at (h, k),
and a focal length |p|

Rewrite x=7y²+3y² in the standard form

4· 140 (x−0)=(y−0)²

Therefore parabola properties are:

(h, k)=(0, 0), p=140

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こんにちは, について質問する vertices 7y²+3y² または以下を選択してください

−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

頂点 7y^2+3y^2

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