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範囲 sqrt(x+3)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
(☐)^′	`ddx`	∂∂`x`	∫	∫_□^□	lim	∑	∞	`θ`	(`f` ◦ `g`)	`f`(`x`)

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x^☐

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log_□

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ddx

≥	≤	·	÷	`x`^◦	(☐)	\|☐\|	(`f` ◦ `g`)	`f`(`x`)	ln	`e`^☐
(☐)^′	∂∂`x`	∫_□^□	lim	∑	sin	cos	tan	cot	csc	sec

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ddn ((n+1)!)

Solution

Γ(n+1+1)ϝ(n+2)

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ddn ((n+1)!)

連鎖法則を適用: Γ(n+1+1)ϝ(n+1+1)ddn (n+1)

=Γ(n+1+1)ϝ(n+1+1)ddn (n+1)

ddn (n+1)=1

=Γ(n+1+1)ϝ(n+1+1)· 1

簡素化

=Γ(n+1+1)ϝ(n+2)

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−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

範囲 sqrt(x+3)

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