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人気のある三角関数 >

sqrt(3)*tan(x)+2sec(x)=1

解

3 \cdot tan (x) + 2 sec (x) = 1

解

x = \frac{5 π}{3} + 2 πn

+1

度

x = 30 0^{\circ} + 36 0^{\circ} n

解答ステップ

3 tan (x) + 2 sec (x) = 1

両辺から

1

を引く

3 tan (x) + 2 sec (x) - 1 = 0

サイン, コサインで表わす

3 \frac{sin ( x )}{cos ( x )} + 2 \cdot \frac{1}{cos ( x )} - 1 = 0

簡素化

3 \frac{sin ( x )}{cos ( x )} + 2 \cdot \frac{1}{cos ( x )} - 1 : \frac{3 sin ( x ) + 2 - cos ( x )}{cos ( x )}

3 \frac{sin ( x )}{cos ( x )} + 2 \cdot \frac{1}{cos ( x )} - 1

3 \frac{sin ( x )}{cos ( x )} = \frac{3 sin ( x )}{cos ( x )}

3 \frac{sin ( x )}{cos ( x )}

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{sin ( x ) 3}{cos ( x )}

2 \cdot \frac{1}{cos ( x )} = \frac{2}{cos ( x )}

2 \cdot \frac{1}{cos ( x )}

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{cos ( x )}

数を乗じる:

1 \cdot 2 = 2

= \frac{2}{cos ( x )}

= \frac{3 sin ( x )}{cos ( x )} + \frac{2}{cos ( x )} - 1

分数を組み合わせる

\frac{3 sin ( x )}{cos ( x )} + \frac{2}{cos ( x )} : \frac{3 sin ( x ) + 2}{cos ( x )}

規則を適用

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{3 sin ( x ) + 2}{cos ( x )}

= \frac{3 sin ( x ) + 2}{cos ( x )} - 1

元を分数に変換する:

1 = \frac{1 cos ( x )}{cos ( x )}

= \frac{sin ( x ) 3 + 2}{cos ( x )} - \frac{1 \cdot cos ( x )}{cos ( x )}

分母が等しいので, 分数を組み合わせる:

\frac{a}{c} \pm \frac{b}{c} = \frac{a \pm b}{c}

= \frac{sin ( x ) 3 + 2 - 1 \cdot cos ( x )}{cos ( x )}

乗算:

1 \cdot cos (x) = cos (x)

= \frac{3 sin ( x ) + 2 - cos ( x )}{cos ( x )}

\frac{3 sin ( x ) + 2 - cos ( x )}{cos ( x )} = 0

\frac{f ( x )}{g ( x )} = 0 \Rightarrow f (x) = 0

3 sin (x) + 2 - cos (x) = 0

両辺に

cos (x)

を足す

3 sin (x) + 2 = cos (x)

両辺を2乗する

(3 sin (x) + 2)^{2} = cos^{2} (x)

両辺から

cos^{2} (x)

を引く

(3 sin (x) + 2)^{2} - cos^{2} (x) = 0

三角関数の公式を使用して書き換える

(2 + sin (x) 3)^{2} - cos^{2} (x)

ピタゴラスの公式を使用する:

cos^{2} (x) + sin^{2} (x) = 1

cos^{2} (x) = 1 - sin^{2} (x)

= (2 + sin (x) 3)^{2} - (1 - sin^{2} (x))

簡素化

(2 + sin (x) 3)^{2} - (1 - sin^{2} (x)) : 4 sin^{2} (x) + 43 sin (x) + 3

(2 + sin (x) 3)^{2} - (1 - sin^{2} (x))

= (2 + 3 sin (x))^{2} - (1 - sin^{2} (x))

(2 + sin (x) 3)^{2} : 4 + 43 sin (x) + 3 sin^{2} (x)

完全平方式を適用する:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

a = 2, b = sin (x) 3

= 2^{2} + 2 \cdot 2 sin (x) 3 + (sin (x) 3)^{2}

簡素化

2^{2} + 2 \cdot 2 sin (x) 3 + (sin (x) 3)^{2} : 4 + 43 sin (x) + 3 sin^{2} (x)

2^{2} + 2 \cdot 2 sin (x) 3 + (sin (x) 3)^{2}

2^{2} = 4

2^{2}

2^{2} = 4

= 4

2 \cdot 2 sin (x) 3 = 43 sin (x)

2 \cdot 2 sin (x) 3

数を乗じる:

2 \cdot 2 = 4

= 43 sin (x)

(sin (x) 3)^{2} = 3 sin^{2} (x)

(sin (x) 3)^{2}

指数の規則を適用する:

(a \cdot b)^{n} = a^{n} b^{n}

= (3)^{2} sin^{2} (x)

(3)^{2} : 3

累乗根の規則を適用する:

a = a^{\frac{1}{2}}

= (3^{\frac{1}{2}})^{2}

指数の規則を適用する:

(a^{b})^{c} = a^{b c}

= 3^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

共通因数を約分する:

2

= 1

= 3

= sin^{2} (x) \cdot 3

= 4 + 43 sin (x) + 3 sin^{2} (x)

= 4 + 43 sin (x) + 3 sin^{2} (x)

= 4 + 43 sin (x) + 3 sin^{2} (x) - (1 - sin^{2} (x))

- (1 - sin^{2} (x)) : - 1 + sin^{2} (x)

- (1 - sin^{2} (x))

括弧を分配する

= - (1) - (- sin^{2} (x))

マイナス・プラスの規則を適用する

- (- a) = a, - (a) = - a

= - 1 + sin^{2} (x)

= 4 + 43 sin (x) + 3 sin^{2} (x) - 1 + sin^{2} (x)

簡素化

4 + 43 sin (x) + 3 sin^{2} (x) - 1 + sin^{2} (x) : 4 sin^{2} (x) + 43 sin (x) + 3

4 + 43 sin (x) + 3 sin^{2} (x) - 1 + sin^{2} (x)

条件のようなグループ

= 43 sin (x) + 3 sin^{2} (x) + sin^{2} (x) + 4 - 1

類似した元を足す:

3 sin^{2} (x) + sin^{2} (x) = 4 sin^{2} (x)

= 43 sin (x) + 4 sin^{2} (x) + 4 - 1

数を足す/引く:

4 - 1 = 3

= 4 sin^{2} (x) + 43 sin (x) + 3

= 4 sin^{2} (x) + 43 sin (x) + 3

= 4 sin^{2} (x) + 43 sin (x) + 3

3 + 4 sin^{2} (x) + 4 sin (x) 3 = 0

置換で解く

3 + 4 sin^{2} (x) + 4 sin (x) 3 = 0

仮定:

sin (x) = u

3 + 4 u^{2} + 4 u 3 = 0

3 + 4 u^{2} + 4 u 3 = 0 : u = - \frac{3}{2}

3 + 4 u^{2} + 4 u 3 = 0

標準的な形式で書く

a x^{2} + b x + c = 0

4 u^{2} + 43 u + 3 = 0

解くとthe二次式

4 u^{2} + 43 u + 3 = 0

二次Equationの公式:

次の場合:

a = 4, b = 43, c = 3

u_{1, 2} = \frac{- 4 3 \pm ( 4 3 ) ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

u_{1, 2} = \frac{- 4 3 \pm ( 4 3 ) ^{2} - 4 \cdot 4 \cdot 3}{2 \cdot 4}

(43)^{2} - 4 \cdot 4 \cdot 3 = 0

(43)^{2} - 4 \cdot 4 \cdot 3

(43)^{2} = 4^{2} \cdot 3

(43)^{2}

指数の規則を適用する:

(a \cdot b)^{n} = a^{n} b^{n}

= 4^{2} (3)^{2}

(3)^{2} : 3

累乗根の規則を適用する:

a = a^{\frac{1}{2}}

= (3^{\frac{1}{2}})^{2}

指数の規則を適用する:

(a^{b})^{c} = a^{b c}

= 3^{\frac{1}{2} \cdot 2}

\frac{1}{2} \cdot 2 = 1

\frac{1}{2} \cdot 2

分数を乗じる:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot 2}{2}

共通因数を約分する:

2

= 1

= 3

= 4^{2} \cdot 3

4 \cdot 4 \cdot 3 = 48

4 \cdot 4 \cdot 3

数を乗じる:

4 \cdot 4 \cdot 3 = 48

= 48

= 4^{2} \cdot 3 - 48

4^{2} \cdot 3 = 48

4^{2} \cdot 3

4^{2} = 16

= 16 \cdot 3

数を乗じる:

16 \cdot 3 = 48

= 48

= 48 - 48

数を引く:

48 - 48 = 0

= 0

u_{1, 2} = \frac{- 4 3 \pm 0}{2 \cdot 4}

u = \frac{- 4 3}{2 \cdot 4}

\frac{- 4 3}{2 \cdot 4} = - \frac{3}{2}

\frac{- 4 3}{2 \cdot 4}

数を乗じる:

2 \cdot 4 = 8

= \frac{- 4 3}{8}

分数の規則を適用する:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{4 3}{8}

共通因数を約分する:

4

= - \frac{3}{2}

u = - \frac{3}{2}

二次equationの解:

u = - \frac{3}{2}

代用を戻す

u = sin (x)

sin (x) = - \frac{3}{2}

sin (x) = - \frac{3}{2}

sin (x) = - \frac{3}{2} : x = \frac{4 π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

sin (x) = - \frac{3}{2}

以下の一般解

sin (x) = - \frac{3}{2}

sin (x)

2 πn

循環を含む周期性テーブル:

x 0 \frac{π}{6} \frac{π}{4} \frac{π}{3} \frac{π}{2} \frac{2 π}{3} \frac{3 π}{4} \frac{5 π}{6} sin (x) 0 \frac{1}{2} \frac{2}{2} \frac{3}{2} 1 \frac{3}{2} \frac{2}{2} \frac{1}{2} x π \frac{7 π}{6} \frac{5 π}{4} \frac{4 π}{3} \frac{3 π}{2} \frac{5 π}{3} \frac{7 π}{4} \frac{11 π}{6} sin (x) 0 - \frac{1}{2} - \frac{2}{2} - \frac{3}{2} - 1 - \frac{3}{2} - \frac{2}{2} - \frac{1}{2}

x = \frac{4 π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

x = \frac{4 π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

すべての解を組み合わせる

x = \frac{4 π}{3} + 2 πn, x = \frac{5 π}{3} + 2 πn

元のequationに当てはめて解を検算する

3 tan (x) + 2 sec (x) = 1

に当てはめて解を確認する

equationに一致しないものを削除する。

解答を確認する

\frac{4 π}{3} + 2 πn :

偽

\frac{4 π}{3} + 2 πn

挿入

n = 1

\frac{4 π}{3} + 2 π 1

3 tan (x) + 2 sec (x) = 1

の挿入向け

x = \frac{4 π}{3} + 2 π 1

3 tan (\frac{4 π}{3} + 2 π 1) + 2 sec (\frac{4 π}{3} + 2 π 1) = 1

改良

- 1 = 1

\Rightarrow 偽

解答を確認する

\frac{5 π}{3} + 2 πn :

真

\frac{5 π}{3} + 2 πn

挿入

n = 1

\frac{5 π}{3} + 2 π 1

3 tan (x) + 2 sec (x) = 1

の挿入向け

x = \frac{5 π}{3} + 2 π 1

3 tan (\frac{5 π}{3} + 2 π 1) + 2 sec (\frac{5 π}{3} + 2 π 1) = 1

改良

1 = 1

\Rightarrow 真

x = \frac{5 π}{3} + 2 πn

グラフ

人気の例

cos^2(a)=2cos^2(a)-1

tan(3b+14)=cot(5b+4)

(2sin(x)-cos(x))(1+cos(x))=sin^2(x)

sec^2(x)+2tan^2(x)=2