quadraticformula 2x^2+x-7=0

解

quadraticformula

x = \frac{- 1 + 57}{4}, x = \frac{- 1 - 57}{4}

十進法表記

x = 1.63745 \dots, x = - 2.13745 \dots

解答ステップ

2 x^{2} + x - 7 = 0

解くとthe二次式

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 7 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 7) = 57

x_{1, 2} = \frac{- 1 \pm 57}{2 \cdot 2}

解を分離する

x_{1} = \frac{- 1 + 57}{2 \cdot 2}, x_{2} = \frac{- 1 - 57}{2 \cdot 2}

x = \frac{- 1 + 57}{2 \cdot 2} : \frac{- 1 + 57}{4}

x = \frac{- 1 - 57}{2 \cdot 2} : \frac{- 1 - 57}{4}

二次equationの解:

x = \frac{- 1 + 57}{4}, x = \frac{- 1 - 57}{4}