逆 25(1/5)^{x-2}-1

解

逆

25 (\frac{1}{5})^{x - 2} - 1

- \frac{ln ( \frac{x + 1}{25} )}{ln ( 5 )} + 2

解答ステップ

y = 25 (\frac{1}{5})^{x - 2} - 1

x

を以下で置き換える:

y

x = 25 (\frac{1}{5})^{y - 2} - 1

y

を解く

x = 25 (\frac{1}{5})^{y - 2} - 1

- \frac{ln ( \frac{x + 1}{25} )}{ln ( 5 )} + 2