What is the f(x)=(-2(x-3)(x+1))/((x-1)(x+2)) ?

The f(x)=(-2(x-3)(x+1))/((x-1)(x+2)) is

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f(x)=(-2(x-3)(x+1))/((x-1)(x+2))

f (x) = \frac{- 2 ( x - 3 ) ( x + 1 )}{( x - 1 ) ( x + 2 )}

Domain : x < - 2 or - 2 < x < 1 or x > 1

Range : - \infty < f (x) < \infty

X Intercepts : (3, 0), (- 1, 0), Y Intercepts : (0, - 3)

Asymptotes : Vertical x = - 2, x = 1, Horizontal y = - 2

Extreme Points : None

Interval Notation

Domain : (- \infty, - 2) \cup (- 2, 1) \cup (1, \infty)

Range : (- \infty, \infty)

Solution steps

Domain of

\frac{- 2 ( x - 3 ) ( x + 1 )}{( x - 1 ) ( x + 2 )} : x < - 2 or - 2 < x < 1 or x > 1

Range of

\frac{- 2 ( x - 3 ) ( x + 1 )}{( x - 1 ) ( x + 2 )} : - \infty < f (x) < \infty

Axis interception points of

\frac{- 2 ( x - 3 ) ( x + 1 )}{( x - 1 ) ( x + 2 )} :

X Intercepts

: (3, 0), (- 1, 0),

Y Intercepts

: (0, - 3)

Asymptotes of

\frac{- 2 ( x - 3 ) ( x + 1 )}{( x - 1 ) ( x + 2 )} :

Vertical

: x = - 2, x = 1,

Horizontal

: y = - 2

Extreme Points of

\frac{- 2 ( x - 3 ) ( x + 1 )}{( x - 1 ) ( x + 2 )} :

None

What is the f(x)=(-2(x-3)(x+1))/((x-1)(x+2)) ?
The f(x)=(-2(x-3)(x+1))/((x-1)(x+2)) is