2y^{''}+3y-2y=0

解

2 y^{^{''}} + 3 y - 2 y = 0

y = c_{1} cos (\frac{t}{2}) + c_{2} sin (\frac{t}{2})

解答ステップ

2 y^{''} (t) + 3 y - 2 y = 0

線形 ODE を解く:

y = c_{1} cos (\frac{t}{2}) + c_{2} sin (\frac{t}{2})

y = c_{1} cos (\frac{t}{2}) + c_{2} sin (\frac{t}{2})