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逆 ((z-8)^2)/(z^2-64)

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`x`²	`x`^□	log_□	√☐	^□√☐	≤	≥	□□	·	÷	`x`^◦	π
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∫ x(x²+1)² dx

Solution

−12(x²+1) +C

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∫ x(x²+1)² dx

u置換積分法を適用する: ∫ 12u² du

=∫ 12u² du

定数を除く: ∫a·f(x)dx=a·∫f(x)dx

=12 · ∫ 1u² du

べき乗則を適用する: −1u

=12 (−1u )

代用を戻す u=x²+1

=12 (−1x²+1 )

簡素化 12 (−1x²+1 ): −12(x²+1)

=−12(x²+1)

定数を解答に追加する

=−12(x²+1) +C

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こんにちは, について質問する ∫ x(x²+1)² dx または以下のオプションから選択してください

不定積分の解き方を説明する

−▭▭	<	7	8	9	÷	`AC`
+▭▭	>	4	5	6	×	☐☐☐
×▭▭	(	1	2	3	−	`x`
▭ \|▭	)	.	0	=	+	`y`

逆 ((z-8)^2)/(z^2-64)

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逆 ((z-8)^2)/(z^2-64)

Solution

Solution steps

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